k+1/k=1-k^2-3k-4/4k

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Solution for k+1/k=1-k^2-3k-4/4k equation: 



k+1/k=1-k^2-3k-4/4k

We move all terms to the left:

k+1/k-(1-k^2-3k-4/4k)=0



Domain of the equation: 4k)!=0

k!=0/1

k!=0

k∈R





Domain of the equation: k!=0

k∈R



We get rid of parentheses

k^2+3k+4/4k+k+1/k-1=0

We calculate fractions


k^2+3k+k+4k/4k^2+4k/4k^2-1=0

We add all the numbers together, and all the variables

k^2+4k+4k/4k^2+4k/4k^2-1=0

We multiply all the terms by the denominator


k^2*4k^2+4k*4k^2+4k+4k-1*4k^2=0

We add all the numbers together, and all the variables

k^2*4k^2+8k+4k*4k^2-1*4k^2=0

Wy multiply elements

4k^4+16k^3-4k^2+8k=0

We do not support ekpression: k^4

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